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Fehler in Kreuzkovarianz 2er Filter
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document.pdf
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@ -23,7 +23,7 @@
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\title{Stochastische Signale und Systeme}
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\subtitle{Zusammenfassung Formeln}
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\subsubtitle{Autor: Daniel Thiem - studium@daniel-thiem.de\\Version 1.0 - 27.09.2012}
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\subsubtitle{Autor: Daniel Thiem - studium@daniel-thiem.de\\Version 1.1 - 15.02.2013}
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\maketitle
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\newpage
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@ -244,7 +244,7 @@ P \left(\lim_{k\rightarrow\infty} |X_k-X|=0\right)=1
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\end{itemize}
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\chapter{Discrete-Time-Fourier-Transformation}
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\section{Abtastung}
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\section{Abtastung} \label{fouriersampling}
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\subsection{Im Zeitbereich}
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Sei $x_c(t)$ das zu abtastende Signal und $T_s=\frac{1}{f_s}$ die Abtastdauer bzw. Abtastfrequenz
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\begin{equation}
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@ -627,7 +627,7 @@ c_{YX}&=\int\limits_{-\pi}^\pi H\freq C_{XX}\freq e^{-j\omega\kappa}\frac{d\omeg
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\begin{subequations}
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\begin{align}
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c_{Y_1Y_2}(\kappa)&=\sum\limits_{k=-\infty}^\infty \sum\limits_{l=-\infty}^\infty h_1(k)h_2(l)\cdot c_{X_1X_2}(\kappa -k+l) \\
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c_{Y_1Y_2}(\kappa)&=\sum\limits_{k=-\infty}^\infty \sum\limits_{l=-\infty}^\infty h_1(k)h_2(l)^*\cdot c_{X_1X_2}(\kappa -k+l) \\
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c_{Y_1Y_2}(\kappa)&=h_1(\kappa)\star h_2(\kappa)^*\star c_{X_1X_2}(\kappa)\\
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C_{Y_1Y_2}\freq &=H_1\freq H_2\freq^*C_{X_1X_2}\freq
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\end{align}
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